Here are graphs representing two functions, and , given by and .
Two graphs representing functions in x y plane, origin O. First graph opens upward, crosses the negative x axis in two places, and crosses the y axis above the origin. Second graph opens upward, crosses the x axis with one negative point and the other at the origin.
Which graph represents each function? Explain how you know.
Where does the graph of meet the -axis? Explain how you know.
17.2
Activity
Shifting the Graph
How would you change the equation so that the vertex of the graph of the new equation is located at the following coordinates and so that the graph opens as described?
, opens upward
, opens upward
, opens downward
Use graphing technology to verify your predictions. Adjust your equations if necessary.
Kiran graphed the equation and noticed that the vertex is at . He changed the equation to and saw that the graph shifted 3 units to the right and the vertex is now at .
Next, he graphed the equation and observed that the vertex is at . Kiran thought, “If I change the squared term to , the graph of will be 5 units to the right and the vertex will be at .”
Do you agree with Kiran? Explain or show your reasoning.
17.3
Activity
A Peanut Jumping over a Wall
17.4
Activity
Smiley Face
Do you see 2 “eyes” and a smiling “mouth” on the graph? The 3 arcs on the graph all represent quadratic functions that were initially defined by , but whose equations were later modified.
Write equations to represent each curve in the smiley face.
What domain is used for each function to create this graph?
Student Lesson Summary
The graphs of , and all have the same shape but their locations are different. The graph that represents has its vertex at .
Three parabolas in x y plane, origin O. X axis negative 8 to 8, by 2’s. Y axis negative 20 to 30, by 10s. First parabola labeled y equals x squared opens upward with vertex at the origin. Second parabola labeled y equals x squared plus 12 opens upward with a vertex at 0 comma negative 12. Third parabola labeled y equals open parenthesis, x plus 3, end parenthesis, squared opens upward with a vertex at negative 3 comma 0.
Notice that adding 12 to raises the graph by 12 units, so the vertex of that graph is at . Replacing with shifts the graph 3 units to the left, so the vertex is now at .
We can also shift a graph both horizontally and vertically.
The graph that represents will have the same shape as but it will be shifted 12 units up and 3 units to the left. Its vertex is at .
Two parabolas in x y plane, origin O. X axis negative 8 to 8, by 2’s. Y axis negative 20 to 30, by 10s. First parabola labeled y equals x squared opens upward with vertex at the origin. Second parabola labeled y equals open parenthesis, x plus 3, closed parenthesis, squared, plus 12 opens upward with a vertex at negative 3 comma 12.
The graph representing the equation has the same vertex at , but because the squared term is multiplied by a negative number, the graph is flipped over horizontally, so that it opens downward.
Two parabolas in x y plane, origin O. X axis negative 8 to 2, by 2’s. Y axis negative 20 to 20, by 20s. Parabola labeled y equals open parenthesis, x plus 3, closed parenthesis, squared, plus 12 opens upward. Parabola labeled y equals negative open parenthesis, x plus 3, end parenthesis, squared, plus 12 opens downward.
Glossary
None
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Mai is learning to create computer animation by programming. In one part of her animation, she uses a quadratic function to model the path of the main character, an animated peanut, jumping over a wall.
Mai uses the equation to represent the path of the jump. represents the height of the peanut as a function of the horizontal distance, , that it travels.
On the screen, the base of the wall is located at , with the top of the wall at . The dashed curve in the picture shows the graph of 1 equation that Mai tried, where the peanut fails to make it over the wall.
Graph of the path of a peanut’s jump. X axis from 0 to 28, by 2s. Y axis from 0 to 7, by 1s. Path starts around 11 comma 0, moves upward to a vertex of 18 comma 5, then hits the wall around 22 comma 3 point 5.
What are the values of and in this equation?
Starting with Mai’s equation, choose values for and that will guarantee that the peanut stays on the screen but also makes it over the wall. Be prepared to explain your reasoning.
Standards Alignment
Building On
Addressing
F-BF.3
Identify the effect on the graph of replacing f(x) by f(x) + k, k f(x), f(kx), and f(x + k) for specific values of k (both positive and negative); find the value of k given the graphs. Experiment with cases and illustrate an explanation of the effects on the graph using technology. Include recognizing even and odd functions from their graphs and algebraic expressions for them.
Identify the effect on the graph of replacing f(x) by f(x) + k, k f(x), f(kx), and f(x + k) for specific values of k (both positive and negative); find the value of k given the graphs. Experiment with cases and illustrate an explanation of the effects on the graph using technology. Include recognizing even and odd functions from their graphs and algebraic expressions for them.
Identify the effect on the graph of replacing f(x) by f(x) + k, k f(x), f(kx), and f(x + k) for specific values of k (both positive and negative); find the value of k given the graphs. Experiment with cases and illustrate an explanation of the effects on the graph using technology. Include recognizing even and odd functions from their graphs and algebraic expressions for them.