100 captive Asian and 100 wild Asian elephants are weighed. There is a meaningful difference between the masses of the 2 groups if the measures of center are at least twice as far apart as the measure of variability. Is there a meaningful difference between the masses of these 2 groups of elephants? Explain your reasoning.
13.2
Activity
Your teacher will give you either a problem card or a data card. Do not show or read your card to your partner.
If your teacher gives you the problem card:
Silently read your card and think about what information you need to answer the question.
Ask your partner for the specific information that you need. “Can you tell me _____?”
Explain to your partner how you are using the information to solve the problem. “I need to know _____ because . . . .”
Continue to ask questions until you have enough information to solve the problem.
Once you have enough information, share the problem card with your partner, and solve the problem independently.
Read the data card, and discuss your reasoning.
If your teacher gives you the data card:
Silently read your card. Wait for your partner to ask for information.
Before telling your partner any information, ask, “Why do you need to know _____?”
Listen to your partner’s reasoning and ask clarifying questions. Only give information that is on your card. Do not figure out anything for your partner!
These steps may be repeated.
Once your partner says they have enough information to solve the problem, read the problem card, and solve the problem independently.
Share the data card, and discuss your reasoning.
13.3
Activity
Standards Alignment
Building On
S-ID.1
Represent data with plots on the real number line (dot plots, histograms, and box plots).
Use statistics appropriate to the shape of the data distribution to compare center (median, mean) and spread (interquartile range, standard deviation) of two or more different data sets.
For each situation, you are given two graphs of data, a measure of center for each, and a measure of variability for each.
Interpret the measure of center in terms of the situation.
Interpret the measure of variability in terms of the situation.
Compare the two data sets.
The heights of the 40 trees in each of two forests are collected.
mean: 44.8 feet, standard deviation: 4.72 feet
Dot plot from 30 to 75 by 1's. Tree height in forest A in feet. Beginning at 30, number of dots above each increment is 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 4, 3, 4, 3, 3, 3, 2, 2, 2, 1, 1, 2, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.
mean: 56.03 feet, standard deviation: 7.87 feet
Dot plot from 30 to 75 by 1's. Tree height in forest B in feet. Beginning at 30, number of dots above each increment is 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 2, 1, 0, 1, 0, 1, 0, 3, 2, 1, 2, 2, 4, 3, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 0, 0, 0, 0, 0.
The number of minutes it takes Lin and Noah to finish their tests in German class is collected for the year.
mean: 29.48 minutes, standard deviation: 5.44 minutes
Dot plot from 10 to 44 by 1's. Time to finish test for Lin in minutes. Beginning at 10, number of dots above each increment is 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 2, 0, 1, 3, 2, 1, 2, 1, 3, 1, 2, 0, 0, 0, 2, 1, 2, 0, 1, 0, 0, 0, 0.
mean: 28.44 minutes, standard deviation: 7.40 minutes
Dot plot from 10 to 44 by 1's. Time to finish test for Noah in minutes. Beginning at 10, number of dots above each increment is 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 2, 2, 1, 1, 0, 1, 1, 1, 1, 3, 1, 1, 1, 0, 2, 0, 0, 0, 0, 2, 1, 0, 0.
The number of raisins in a cereal with a name brand and the generic version of the same cereal are collected for several boxes.
mean: 289.1 raisins, standard deviation: 19.8 raisins
Histogram from 200 to 330 by 10’s. Number of raisings in brand cereal. Beginning at 200 up to but not including 210, height of bar at each interval is 0, 0, 0, 0, 0, 3, 2, 3, 7, 7, 3, 2, 3, 0.
mean: 249.17 raisins, standard deviation: 26.35 raisins
Histogram from 200 to 330 by 10’s. Number of raisings in brand cereal. Beginning at 200 up to but not including 210, height of bar at each interval is 2, 3, 2, 4, 5, 4, 2, 3, 3, 2, 0, 0, 0, 0.
Student Lesson Summary
The more variation a distribution has, the greater the standard deviation. A more compact distribution will have a lesser standard deviation.
The first dot plot shows the number of points that a player on a basketball team made during each of 15 games. The second dot plot shows the number of points scored by another player during the same 15 games.
Dot plot from 1 to 17 by 1's. Points for player one. Beginning at 1, number of dots above each increment is 3, 2, 3, 1, 3, 0, 1, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0.
Dot plot from 1 to 17 by 1's. Points for player two. Beginning at 1, number of dots above each increment is 0, 3, 0, 2, 0, 3, 0, 1, 0, 3, 0, 0, 0, 1, 0, 2, 0.
The data in the first plot have a mean of approximately 3.87 points and standard deviation of about 2.33 points. The data in the second plot have a mean of approximately 7.73 points and a standard deviation of approximately 4.67 points. The second distribution has greater variability than the first distribution because the data are more spread out. This is shown in the standard deviation for the second distribution being greater than the standard deviation for the first distribution.
Standard deviation is calculated using the mean, so it makes sense to use it as a measure of variability when the mean is appropriate to use for the measure of center. In cases where the median is a more appropriate measure of center, the interquartile range is still a better measure of variability than standard deviation.
None
Standards Alignment
Building On
Addressing
Building Toward
S-ID.2
Use statistics appropriate to the shape of the data distribution to compare center (median, mean) and spread (interquartile range, standard deviation) of two or more different data sets.
Use statistics appropriate to the shape of the data distribution to compare center (median, mean) and spread (interquartile range, standard deviation) of two or more different data sets.